Question #60b08 Chemistry Solutions Percent Concentration 1 Answer anor277 May 4, 2017 #"Mole fraction, "chi_n="Moles of solute"/"Moles of all components in the solution"# Explanation: And thus #"moles of glucose"=(90*g)/(180.16*g*mol^-1)=0.50*mol#. And #"moles of urea"=(30*g)/(60.06*g*mol^-1)=0.50*mol#. And #"moles of water"=(162*g)/(18.01*g*mol^-1)=9.0*mol#. So #chi_"glucose"=(0.50*mol)/((0.50+0.50+9.0)*mol)=0.05.# And #chi_"urea"=(0.50*mol)/((0.50+0.50+9.0)*mol)=0.05.# And #chi_"water"=(9.0*mol)/((0.50+0.50+9.0)*mol)=0.90.# By the very way we define #"mole fraction"#, their SUM should be unity. Is this true in this case? Answer link Related questions How can the concentration of water in solution be decreased? How can the concentration of a solution be increased? How do you find the concentration of a solution in ppm? How do you make a 10 percent solution? How do you make a 2 percent solution? What is the weight per volume method to calculate concentration? What percent concentration of KCl would be isotonic? What is the percent concentration of sodium chloride in normal saline? What is the percent concentration of a 6m solution of NaCl? What is the percent concentration formula? See all questions in Percent Concentration Impact of this question 1620 views around the world You can reuse this answer Creative Commons License