What mass of solute is contained in a #675mL# volume of solution that was #0.025mol*L^-1# with respect to #"sodium sulfate"#?

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Answer 1 · 2017-04-26T20:09:59

We get a mass of under #2.5*g# of dissolved solute.

#"Concentration"="Moles of solute"/"Volume of solution"#, and thus, more symbolically, #C=n/V#.

As you progress in chemistry, you will use this relationship #"ad nauseum"#.

Given the formula:

#"moles"="concentration"xx"volume".# And thus..........

#n_(Na_2SO_4)=0.025*mol*cancel(L^-1)xx675*cancel(mL)xx10^-3cancel(L*mL^-1)#

#=0.016875*mol#, note that dimensionally, the units we got were #"moles"#.

And for the mass of this quantity, we perform the product, #"mass"xx"molar mass"# #=# #0.016875*cancel(mol)xx142.04*g*cancel(mol^-1)#
#=??g#

What mass of solute is contained in a #675*mL# volume of solution that was #0.025*mol*L^-1# with respect to #"sodium sulfate"#?