If 12*L of hydrogen gas react with 12*L of chlorine gas, what volume of HCl(g) will result?

1 Answer
Apr 19, 2017

The volume of a gas is equivalent to the number of molecules it contains under equivalent temperature and pressure. And thus we should get 22.4*L HCl(g).

Explanation:

We interrogate the reaction:

1/2H_2(g) + 1/2Cl_2(g) rarr HCl(g),

equivalently,

H_2(g) + Cl_2(g) rarr 2HCl(g),

Given the opening statement, i.e. which is due to Avogadro, the volumes are proportional to the number of molecules each gas contains. Dihydrogen gas is present in HALF MOLAR proportion, and dichlorine is present in excess. And thus, given complete reaction, 11.2*L of H_2 reacts with 11.2*L of Cl_2 to give 22.4*L HCl(g).

All of this is based on the stoichiometric equation..........