What is the concentration of an $18.9g$ mass of ammonium nitrate dissolved in an $855mL$ volume of solution?

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Answer 1 · 2017-04-18T18:12:58

$"Molarity"-="Moles of solute"/"Volume of solution"-=0.276*mol*L^-1$ .

$"Molarity"=((18.9*g)/(80.05*g*mol^-1))/(0.855*L)=0.276*mol*L^-1$ .

And all we did here was to apply the definition of $"molarity"$ , i.e. $"moles of solute per unit volume of solution"$ .

Would this solution be slightly acidic or slightly basic........?

What is the concentration of an 18.9*g18.9*g mass of ammonium nitrate dissolved in an 855*mL855*mL volume of solution?