Question #6ec6f

1 Answer
P dilip_k
Apr 18, 2017

The mass % or #w/w# % of the #H_2SO_4# solution is #29%#
This means #100# g of the solution contains #29# g or #(29g)/(98g"/"mol)=29/98 mol # #H_2SO_4#.
Now let the density of the solution be #d# #g"/"mL#

So volume of 100 g #H_2SO_4# solution is #100/d# mL or
#0.1/d# L

So molarity of the solution is #(29/98)/(0.1/d)# M

So by the problem

#(29/98)/(0.1/d)=3.6#

#=>d =(3.6xx9.8)/29~~1.2# #g"/"mL#

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