What volume of #"lithium sulfite solution"# of #2.50molL^-1# concentration would contain a mass of #422.55*g#?

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Answer 1 · 2017-04-17T20:14:47

#"Moles of lithium sulfite req'd..........."=(422.55*g)/(93.94*g*mol^-1)=#

#=(422.55*g)/(93.94*g*mol^-1)=4.50*mol#.

And since #"concentration"="moles"/"volume"#, we need the quotient..........

#"volume"="moles"/"concentration"=(4.50*mol)/(2.50*mol*L^-1)=1.80*1/L^-1#

#1.80*1/(1/L)=1.80*L#

In practice, water is quite an involatile material. You would not evaporate this quantity of water.

What volume of #"lithium sulfite solution"# of #2.50*mol*L^-1# concentration would contain a mass of #422.55*g#?