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Question #20e44

1 Answer

Apr 16, 2017

#oo#

Explanation:

#(x^2+sin^2x+xsinx)/sin^3x = 1/sinx(x^2/sin^2x+1+x/sinx)#

so

#lim_(x->0)(x^2+sin^2x+xsinx)/sin^3x=lim_(x->0)(1/sinx)lim_(x->0)(x^2/sin^2x+1+x/sinx)=1/0(3)=oo#

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