Question #6ad49

2 Answers
Jim G.
Apr 15, 2017

#log6^(1/3)#

Explanation:

Using the #color(blue)"law of logarithms"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(logx^nhArrnlogx)color(white)(2/2)|)))#

#rArr(log6)/3=1/3log6=log6^(1/3)#

Douglas K.
Apr 15, 2017

Please see the explanation.

Explanation:

Given: #(log(6))/3#

The above can be written as:

#(1/3)log(6)#

Use the property of logarithms #(c)log(a) = log(a^c)#:

#log(6^(1/3))#

We know that the #1/3# power is the same as the cube root:

#log(root3(6)) larr# the answer.

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