Question #6ad49

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Question #6ad49

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Answer 1 · 2017-04-15T16:44:13

$log6^(1/3)$

Explanation:

Using the $color(blue)"law of logarithms"$

$color(red)(bar(ul(|color(white)(2/2)color(black)(logx^nhArrnlogx)color(white)(2/2)|)))$

$rArr(log6)/3=1/3log6=log6^(1/3)$

Answer 2 · 2017-04-15T16:45:10

Please see the explanation.

Explanation:

Given: $(log(6))/3$

The above can be written as:

$(1/3)log(6)$

Use the property of logarithms $(c)log(a) = log(a^c)$ :

$log(6^(1/3))$

We know that the $1/3$ power is the same as the cube root:

$log(root3(6)) larr$ the answer.

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Question #6ad49

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