Question #5d751

1 Answer
Jul 7, 2017

It's because the #"C-F"# bond is shorter than the #"C-Cl"# bond.

Explanation:

The dipole moment #µ# of a diatomic molecule is a measurement of the separation of two opposite electrical charges.

The magnitude of the moment is equal to the charge #q# multiplied by the distance #r# between them.

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www.doitpoms.ac.uk

#"CH"_3"Cl"# and #"CH"_3"F"# are not diatomic molecules, but most of their dipole moment is caused by the polarities of the #"C-Cl"# and #"C-F bonds"#.

Here's a simple argument to account for the differences in dipole moment.

#"F"# is more electronegative than #"Cl"#, but the #"C-F"# bond is only 72 % as long as a #"C-Cl"# bond (139 pm vs 178 pm).

Thus, the charge separation in a #"C-F"# bond would have to be 39 % greater than that in a #"C-Cl"# bond to generate the same dipole moment (#0.72 × 1.39 = 1.00#).

The #"C-F"# bond polarity is not great enough to compensate for the shorter bond distance, so #"CH"_3"F"# has a smaller dipole moment than #"CH"_3"Cl"#.