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Question #3a14d

1 Answer

Apr 14, 2017

Given
#cosecx+sinx=2#

#=>1/sinx+sinx=2#

#=>1+sin^2x=2sinx#

#=>1+sin^2x-2sinx=0#

#=>(1-sinx)^2=0#

#=>1-sinx=0#

#=>sinx=1#

and #cosecx=1#

Now

#cosec^nx+sin^nx#

#=1^n+1^n=2#

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