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Question #9e5bf

1 Answer

Apr 12, 2017

Please see the explanation

Explanation:

Given: #2sin^2(theta) =2+cos(2theta)#

Use the identity #1 -2sin^2(theta)=cos(2theta)#:

#2sin^2(theta) =2+1 -2sin^2(theta)#

Add #2sin^2(theta)# to both sides:

#4sin^2(theta) =3#

#sin^2(theta) = 3/4#

#sin(theta) = +-sqrt(3)/2#

From 0 to #2pi#

#theta = pi/3, (2pi)/3, (4pi)/3, and (5pi)/3#

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