Question #f9cf5

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anor277
Apr 14, 2017

2.50*mol of CaCl_2 are necessary..........................

Explanation:

We use the relationship:

"Concentration" = "Moles of solute"/"Volume of solution".

And thus "Moles of solute"="Concentration"xx"Volume of solution"

=5*mol*L^-1xx500*mLxx10^-3*L*mL^-1=2.50*mol

What is the mass of this molar quantity?

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