Question #c0ad9

1 Answer
P dilip_k
Aug 19, 2017

1+2cscx=cotx+3cscx

=>sinx( 1+2/sinx)=sinx(cosx/sinx+3/sinx)

=>sinx+2=cosx+3

=>1/sqrt2sinx-1/sqrt2cosx=1/sqrt2

=>cos(pi/4)sinx-sin(pi/4)cosx=sin(pi/4)

=>sin(x-pi/4)=sin(pi/4)

=>x-pi/4=npi+(-1)^npi/4" where " nin ZZ

=>x=npi+(-1)^npi/4+pi/4" where " nin ZZ

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