Question #4536d

1 Answer
Douglas K.
Apr 7, 2017

theta ~~ 230^@ or theta ~~ 4" radians"

Explanation:

We know that the angle must be in the Third Quadrant, because the signs of both of the components are negative, therefore, we must add 180^@ or pi" radians" to the inverse tangent function:

theta = tan^-1(y/x)+180^@ or theta = tan^-1(y/x)+pi" radians"

theta = tan^-1((-4)/-3)+180^@ or theta = tan^-1((-4)/-3)+pi" radians"

theta ~~ 230^@ or theta ~~ 4" radians"

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