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Question #05f79

1 Answer

Apr 7, 2017

#a^(-5) = 1/a^5#

Explanation:

Use the exponent rules #(x^m)^n = x^(m*n) " and " x^m x^n = x^(m-n)#

#a^4/(a^3)^3 = a^4/a^9 = a^(4-9) = a^-5#

When you have a negative exponent in the numerator, you can move the exponent to the denominator and make it positive #x^(-m) = 1/x^m#

This means #a^-5 = 1/a^5#

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