Question #ca3b0

2 Answers
Apr 7, 2017

You need to interrogate the alkane MELTING points...........as a physical scientist you need to interpret data NOT to estimate it.

Explanation:

And of course, you need to examine the actual [data.](https://en.wikipedia.org/wiki/Higher_alkanes) From the table, hexadecane, n-C_16H_34, has a melting point of 18.2 ""^@C; branched alkanes should have LOWER melting points. Can you advance a reason why?

Apr 7, 2017

You need a graph of alkane melting points.

Explanation:

It should look something like this:

![Alkane http://m.p.](https://useruploads.socratic.org/q7sOYckRVydVTFRqeiI7_M.p.+alkanes.jpg)

You might define 20 °C as room temperature.

Then you would check the melting points of the alkanes from one carbon up.

The dividing line appears to come between hexadecane (16 carbons, melting point 18 °C) and heptadecane (17 carbons, melting point 21 °C).

Then, heptadecane would the first alkane to be a solid at room temperature.