What is the formality of a $1.24g$ mass of $"copper sulfate pentahydrate"$ in a $100cm^3$ volume of solution?

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Answer 1 · 2017-04-07T15:40:40

$"Formality"$ $=$ $"Moles of solute"/"Volume of solution (L)"=0.05*mol*L^-1$ .

$"Concentration of sodium thiosulfate pentahydrate:"$

$-=$ $((1.24*g)/(248.18*g*mol^-1))/(100*cm^3xx10^-3*cm^-3*L)$

$=0.0500*mol*L^-1$ WITH RESPECT TO THE PENTAHYDRATE.

What is the formality of a 1.24*g1.24*g mass of "copper sulfate pentahydrate""copper sulfate pentahydrate" in a 100*cm^3100*cm^3 volume of solution?