Question #b59c9

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Answer 1 · 2017-04-05T17:27:44

$308$ $308$ ml(3s.f.)

first, convert $1.50$ $1.50$ atm to torr:

$1$ $1$ atm = $760$ $760$ torr

$1.5$ $1.5$ atm $(p_{2})$ $(p_2)$ = $760 \cdot 1.5$ $760*1.5$ torr = $1140$ $1140$ torr

new pressure $(p_{2}) :$ $(p_2):$ 1140# torr

boyle's law: $p$ $p$ (pressure) * $v$ $v$ (volume) = constant
$p_{1} \cdot v_{1} =$ $p_1 * v_1 =$ constant
$p_{2} \cdot v_{2} =$ $p_2*v_2=$ constant

here, the constant is $1140$ $1140$ torr * $250$ $250$ ml = $285, 000$ $285,000$ .
$p_{2} \cdot v_{2} = 285, 000$ $p_2*v_2 = 285,000$

$therefore p_1*v_1 = 285000$

$p_1 = 925$ torr

$v_1 = 285000/925$ ml = $308$ ml (3s.f.)