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Answer 1 · 2017-04-05T14:38:36

#27.4g (3s.f.)#

#2C_4H_10+13O_2->10H_2O+8CO_2#

relative formula mass #(M_r)# of #2C_4H_10#:

#A_m(C)=12#
#A_m(H)=1#

#M_r(2C_4H_10) = 2*(4*12+10*1)#
#=2*58#
#=116#

#M_r(2C_4H_10) = 116#

#M_r(8CO_2) = 8*(12+(2*16)) = 8*44#
#=352#

#M_r(2C_4H_10) = 116#
#M_r(CO_2) = 44#

#(M_r(2C_4H_10))/(M_r(CO_2)) =# mass of butane needed/#(83.0g)#

#116/352=29/88= #mass of butane needed/#(83.0g)#

mass of butane needed = #29/88 * 83.0g#
#= 27.4g (3 s.f)#