Question #83f4d

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Question #83f4d

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Answer 1 · 2017-04-04T02:19:54

You need $"0.17 L"$ of the $"12.0 M"$ solution.

Explanation:

Molarity (M) is a unit of concentration in solutions. If a solution has a molarity of 2, we would identify it as 2M, and we say it is 2 molar. M means mol/L. So a 2M solution has a concentration of 2 mol/L.
The formula that allows you to answer this question is:

$M_1V_1=M_2V_2$

where $M_1$ and $M_2$ are the molarity of the solutions in mol/L, and $V_1$ and $V_2$ are the volume of the solutions in liters.

Known
$M_1="12.0 mol/L"$
$M_2="1.0 mol/L"$
$V_2="2.0 L"$

Unknown : $V_1$

Solution
Rearrange the equation to isolate $V_1$ . Substitute the known values into the equation and solve.

$V_1=(M_2V_2)/M_1$

$V_1=(1.0color(red)cancel(color(black)("mol"))/color(red)cancel(color(black)("L"))xx2.0"L")/(12.0color(red)cancel(color(black)("mol"))/color(red)cancel(color(black)("L"))$ $=$ $"0.17 L"$ rounded to two significant figures

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Question #83f4d

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