Question #988dd

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Question #988dd

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Answer 1 · 2017-04-02T17:33:09

$ZnCl_2 + Na_2CO_3 rarr ZnCO_3 + 2 NaCl$

Explanation:

$ZnCl_2 + Na_2CO_3 rarr ZnCO_3 + NaCl$

This is what I do...
I write that all elements on the reactant side as well as those on the product side. Not forgetting to split them when there is an addition.

Reactants

$Zn=1$
$Cl=2$
$+$
$Na=2$
$C=1$
$O=3$

Products

$Zn=1$
$C=1$
$O=3$
$+$
$Na=1xxcolor(red)2=2$
$Cl=1xxcolor(red)2=2$

From the above, we see that $Na$ is $2$ on the reactant side and $1$ on the product side so we multiply by $color(red)2$ to make it equal. When you do this, it automatically affects $Cl$ because it forms a compound.

Check to see if all elements are balanced then rewrite the equation.

$ZnCl_2 + Na_2CO_3 rarr ZnCO_3 + color(red)2 NaCl$

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Question #988dd

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