Question #f97c6 Chemistry Solutions Molarity 1 Answer anor277 Jun 22, 2017 Approx......#80*mL# Explanation: We need a molar quantity of #(22.0*g)/(213.9*g*mol^-1)=0.103*mol# with respect to #"aluminum nitrate"#. Because #"concentration"="moles of solute"/"volume of solution (L)"#, we needs the quotient........ #"volume"="moles of solute"/"concentration"# #=(0.103*mol)/(1.25*mol*L^-1xx10^-3*L*mL^-1)# #=82.3*mL#, note that #1/(mL^-1)=1/(1/(mL))=mL# as required......... Answer link Related questions what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... How can molarity and osmolarity be calculated from mass per unit volume? How can molarity be used as a conversion factor? How high can molarity be? How does molarity change with temperature? How do you find molarity of a solution? What is the molarity of 10 NaOH? What is the molarity of 3 hydrogen peroxide? What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? What is molarity? See all questions in Molarity Impact of this question 1562 views around the world You can reuse this answer Creative Commons License