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Question #6a1a5

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Mar 29, 2017

#(sin2x)/(1-2cos2x)#

#=(sin2x)/(sin^2x+cos^2x-2(cos^2x-sin^2x))#

#=(sin2x)/(sin^2x+cos^2x-2cos^2x+2sin^2x)#

#=(2sinxcosx)/(3sin^2x-cos^2x)#

#=((2sinxcosx)/cos^2x)/((3sin^2x)/cos^2x-cos^2x/cos^2x)#

#=(2tanx)/(3tan^2x-1)#

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