Question #5d932

1 Answer
Nathan L.
Jul 16, 2017

#V_1 = 318# #"mL"#

Explanation:

We're asked to find the original volume of #"F"_2# using gas equations.

To do this, we can use the pressure-volume relationship of gases, illustrated by Boyle's law:

#P_1V_1 = P_2V_2#

where

  • #P_1# is the original pressure, given as #900.# #"torr"#

  • #V_1# is the original volume (what we're trying to find)

  • #P_2# is the final pressure, given as #1.5# #"atm"#

  • #V_2# is the final volume, given as #250.# #"mL"#

We need the units for pressure to be consistent, so let's convert the #900# #"torr"# quantity to #"atm"#:

#900cancel("torr")((1color(white)(l)"atm")/(760cancel("torr"))) = 1.18# #"atm"#

Plugging in known values, and solving for the original volume, #V_1#, we have

#V_1 = (P_2V_2)/(P_1) = ((1.5cancel("atm"))(250color(white)(l)"mL"))/(1.18cancel("atm")) = color(red)(318# #color(red)("mL"#

which I'll round to #3# significant figures, the amount given for the other volume measurement.

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