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Question #f1a06

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Mar 29, 2017

#sin = sqrt 56/9#, #cos = 5/9#, and #tan = sqrt 56/5#

Explanation:

#sec = 1/cos# = #9/5#, #= 5/9#

based on pyhtogoras theoram for triangle,

#sin = sqrt(9^2 - 5^2)/9 = sqrt 56/9#, and

#tan = sqrt 56/5#, we also can use #sin/cos#

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