If carbon dioxide expresses a #1"ppm"# concentration in water, what is its concentration in #molL^-1#?

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Answer 1 · 2017-03-25T07:20:29

Well #"1 ppm "-=" 1 mg"*L^-1............#

And so you simply multiply the #"ppm"# concentration by #(1xx10^-3*g*L^-1)/(44.0*g*mol^-1)# to give a molar concentration in #mol*L^-1#.

If carbon dioxide expresses a #1*"ppm"# concentration in water, what is its concentration in #mol*L^-1#?