Question #17019

1 Answer
P dilip_k
Mar 23, 2017

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We have been given a cuboid having

"length "(l)=8cm=0.08m

"height "(h)=6cm=0.06m

"width "(w)=4cm=0.04m

and

"weight"(W)=100N

It is obvious that two surfaces having smallest area comprising height and width will have area A = hxxw =0.06xx0.04m^2=24xx10^-4m^2

When the cuboid is kept on the table keeping its surface of minimum area on it then the pressure (force exerted on unit area perpendicularly) on the table by its weight will be maximum and this will be given by

P_"max"=W/A=100/(24xx10^-4)N"/"m^2

=4.16xx10^4Pa

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