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Prove that #(sin2x-cos2x)/(sinxcosx)=-cot2x#?

1 Answer

Shwetank Mauria

Mar 20, 2017

#(sin^2x-cos^2x)/(sinx cosx)=-cot2x#

Explanation:

I presume you mean

#(sin^2x-cos^2x)/(sinx cosx)#

and this can be written as

#-(cos^2x-sin^2x)/(2sinx cosx)xx2#

= #-(cos2x)/(sin2x)xx2#

= #-2cot2x#

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