Question #7af81

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Question #7af81

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Answer 1 · 2017-03-18T13:36:59

#sin t = +- 4/5#

Explanation:

#cos t = 3/5#
#sin^2 t = 1 - cos^2 t = 1 - 9/25 = 16/25#
#sin t = +- 4/5#
There are 2 opposite values of sin t.
On the trig unit circle:
#cos t = 3/5# --> #t = +- 53^@13# -->
a. If t = 53.13 --> #sin t = 4/5#
b. If t = - 53.13 --> #sin t = - 4/5#

Answer 2 · 2017-03-18T14:07:47

#4/5# or #0.8#

Explanation:

#Cos theta=3/5=0.6#

#:.Arc cos(Cos^-1)0.6=(53.13010235°) 53°7'48.37''#

#:.theta=53°7'48.37''#

#:.Sin theta=0.8# or #4/5#

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Question #7af81

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