Question #856ce

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Answer 1 · 2017-03-16T19:51:12

#t=3 7/9" minutes "larr# Exact time

#t=3.77bar7" minutes " larr# approximate time

Let time in minutes be #t#

Distance from ground level:

Going down#-> 1800 - 250t#
Going up#" "->color(white)(1)100+200t#

When you meet you will both be at the same height above ground level

#1800-250t=100+200t#

#1800-100=200t+250t#

#1700=450t#

#t=1700/450#

#t=3 7/9" minutes "larr# Exact time

#t=3.77bar7" minutes " larr# approximate time