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Question #d0dcc

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Mar 19, 2017

Given #" "tanA=1/3->+ve=>cotA=3#

and #" "cosA->-ve#

So angle #Ain "III Quadrant" # where #" sinA->-ve#

So #sinA=1/csca=-1/sqrt(1+cot^2A)=-1/sqrt(1+3^2)#

#=-1/sqrt10=-sqrt10/10#

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