Question #2e732

1 Answer
P dilip_k
Mar 11, 2017

The building's height h=200m.
So the barometer reading at lower floor is higher than the upper floor due to the pressure exerted by 200m air column.

Pressure exerted by the air column
=h xxd xxg
Where d= "density of air and g = acceleration due to gravity"

The barometer reading difference gives the pressure difference of 76-74.15=1.85cm=1.85 xx10^-2m of Hg column.

Here the barometric pressure difference is equal to the pressure of 200m air column.

Let the density of air be d "kg/" m^3

So

200xxd xxg=(76 -74.15)xx10^-2xx13600xxg

d=(1.85xx10^-2xx13600)/200"kg/"m^3

=1.285" kg/"m^3

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