Question #4d789

1 Answer
Mar 3, 2017

#4/13.#

Explanation:

Suppose, Event #D=#Pat picked a Diamond Card from pack, and,

Event #J=#pat picked a Jack from pack.

Then, Reqd. Prob.

#=P(DuuJ)=P(D)+P(J)-P(DnnJ)................(star).#

#(star1):P(D):-#

There are #52# cards in a pack, out of which #1# card can be

selected in #52# ways. Hence, the total no. #n# of outcomes is,

#n=52.#

There are #13# Diamond Cards in a pack, so, #1# such card can

be selected in #13# ways. Hence, the total no. #r# of outcomes

favorable to the occurance of the event #D# is, #r=13.#

#:. P(D)=r/n=13/52.....................(star1).#

#(star2): P(J):- "Similarly, "P(J)=4/52.................(star2).#

#(star3): P(DnnJ):-#

Event #DnnJ=#Card picked is a Jack of Diamond.

As discussed above, we have, #P(DnnJ)=1/52........(star3).#

Utilising #(star1), (star2) and (star3) in (star)#, we have,

#"The Reqd. Prob.="13/52+4/52-1/52=16/52=4/13.#

Enjoy Maths.!