The equation for the reaction is
#"2HCl + Ca(OH)"_2 → "CaCl"_2 + 2"H"_2"O"#.
1. Calculate the moles of #"HCl"#
#"Moles of HCl" = "0.025 00" color(red)(cancel(color(black)("L HCl"))) ×( "0.500 mol HCl")/(1 color(red)(cancel(color(black)("L HCl")))) = "0. 012 50 mol HCl"#
2. Calculate the moles of #"Ca(OH)"_2#
#"Moles of Ca(OH)"_2 = "0.012 50" color(red)(cancel(color(black)("mol HCl"))) × ("1 mol Ca(OH)"_2)/(2 color(red)(cancel(color(black)("mol HCl")))) = "0.006 250 mol Ca(OH)"_2"#
3. Calculate the molarity of the #"Ca(OH)"_2#
#"Volume of Ca(OH)"_2 = "0.006 250" color(red)(cancel(color(black)("mol Ca(OH)"_2))) × ("1 L Ca(OH)"_2)/(0.750 color(red)(cancel(color(black)("mol Ca(OH)"_2)))) = "0.008 33 L" = "8.33 mL"#
