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Question #78bc0

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Mar 1, 2017

#6sin^4x#

#=6/4xx(2sin^2x)^2#

#=3/2xx(1-cos2x)^2#

#=3/2xx(1-2cos2x+cos^2 2x)#

#=3/2xx(1-2cos2x+1/2(1+cos4x))#

#=3/4xx(3-4cos2x+cos4x))#

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