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Question #b9d80

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1 Answer

Feb 27, 2017

#sin 495°=1/(√2)#

#=>sin(90xx5+45)°=1/(√2)#

#=>cos45=1/sqrt2#

#sin375=sin(90xx4+15)=sin15#

#=sin(60-45)=sin60cos45-cos60sin45#

#=sqrt3/2xx1/sqrt2-1/2xx1/sqrt2#

#=(sqrt3-1)/(2sqrt2)#

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