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Question #747f2

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Jan 1, 2018

#f(x)={(x+1", "x<1),(1" , "x>1):}#

#lim_(xrarr1^+)f(x)=lim_(xrarr1^+)1=1#

#lim_(xrarr1^-)f(x)=lim_(xrarr1^-)(x+1)=2#

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