Question #3fb7d
1 Answer
You have no way of knowing.
Explanation:
The information provided by the problem can only get you the volume of carbon dioxide produced by the reaction. In order to determine the mass of carbon dioxide, you must know the pressure and temperature at which the reaction takes place.
So, the balanced chemical equation that describes your reaction looks like this
#color(blue)(2)"CO"_ ((aq)) + "O"_ (2(g)) -> color(darkorange)(2)"CO"_ (2(g))#
Notice that the for every
When all the three gases are kept under the same conditions for pressure and temperature, this mole ratio becomes equivalent to a volume ratio.
You can thus say that when
Notice that this is exactly how many liters of carbon monoxide and oxygen gas you have, so you know that the reaction will produce
In order to be able to find the mass of the sample, you must know the pressure and temperature at which the reaction takes place.
Let's say, for example, that the reaction takes place at a pressure
#PV = nRT implies n = (PV)/(RT)#
Here
#R# is the universal gas constant, usually given as#0.0821("atm" * "L")/("mol" * "K")#
In your case, you would have
#n = (P color(red)(cancel(color(black)("atm"))) * 2 color(red)(cancel(color(black)("L"))))/(0.0821(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * T color(red)(cancel(color(black)("K"))))#
#n = 24.36 * P/Tcolor(white)(.)"moles"#
To convert this to grams, use the molar mass of carbon dioxide
#24.36 * P/T color(red)(cancel(color(black)("moles CO"_2))) * "44.01 g"/(1color(red)(cancel(color(black)("mole CO"_2)))) = (1072 * P/T)" g"#
You can use this general solution for any value of