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Question #ee8e8

1 Answer

Feb 19, 2017

(A)

Explanation:

From Ohm's law we know that
#V=IR# ......(1)
Also we know that Power #P# dissipated in a circuit is
#P=V^2/R# ........(2)

When Voltage #V# is doubled
from (1) we get
#2V=I_dR# ......(3)
Dividing (3) with (1)
#(2V)/V=(I_dR)/(IR)#
#=>I_d=2I#

Similarly from (2) we get
#P_d=(2V)^2/R# .....(4)
Dividing (4) with (2) we get
#P_d/P=((2V)^2/R)/(V^2/R)#
#=>P_d=4P#

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