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What is the simplest radical form of #sqrt64#?

1 Answer

Feb 20, 2017

#sqrt64 = sqrt(2^6) =+-8#

Explanation:

The "simplest radical form" of #sqrt 64# is #sqrt (2^6)# if we define "simplest form" as a radical of a prime to an integer power.

However. since #sqrt (2^6) = +-2^3#

The simplest answer to this question is #+-8#

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