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Answer 1 · 2017-02-13T18:10:38

0.095 cms /sec

Let volume of water in the cylindrical tank be V litres, when water has an height of 'h' metres. Volume of water would be $π h$ $pi h$ cubic metres

V= $1000 π h$ $1000 pi h$ (because 1 cubic metre equal 1000 litres)

Differentiating both sides, it would be

$\frac{d V}{d t} = 3 = 1000 π \frac{d h}{d t}$ $(dV)/dt= 3= 1000 pi (dh)/dt$

Rate of change of height $\frac{d h}{d t} = \frac{3}{1000 π}$ $(dh)/dt=3/(1000pi)$ = 0.000955 m/s=0.095 cms/s