Solve the equation $5^x=4^(x+1)$ ?

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Answer 1 · 2017-03-05T08:39:40

$x=6.213$

As $5^x=4^(x+1)$ , taking logarithm on both sides we get

$xlog5=(x+1)log4$

or $x(log5-log4)=log4$

or $x=log4/(log5-log4)$

or $x=log4/log(5/4)$

or $x=log4/log1.25=0.60206/0.09691=6.213$

Solve the equation 5^x=4^(x+1)5^x=4^(x+1)?