Question #2fa3d

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Answer 1 · 2017-02-12T00:05:06

#(− sec ( x ) tan^2 ( x ) − ( 9 − sec ( x ) ) sec^2 ( x ))/tan^2 x#

#=(− sec ( x ) (sec^2 ( x ) -1)− ( 9 − sec ( x ) ) sec^2 ( x ))/tan^2 x#

#=(− sec^3 ( x )+ secx− 9sec^2x + sec^3 ( x ))/tan^2 x#

#=(secx− 9sec^2x )/tan^2 x#

#=secx/tan^2x− (9sec^2x)/tan^2 x#

#=cosx xxcsc^2x− 9csc^2x#