Question #2b1f4

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Question #2b1f4

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Answer 1 · 2017-02-10T01:37:13

$2.0 \times 10^{3} Pa$ $2.0xx10^3" Pa"$

Explanation:

![upload.wikimedia.org]( useruploads.socratic.org )

As shown in the figure bottom face of the sample is held rigidly bound and a shearing/tangential force $F$ $F$ is applied on upper face of area $A$ $A$ . The modulus of rigidity $G$ $G$ is defined as the ratio of shear stress to the shear strain.

Shear stress $= \frac{F}{A}$ $=F/A$ and
shear strain $=tan theta=(Deltax)/l$
$Delta x$ is the transverse displacement of the area on which force is acting and $l$ is the initial length of the side.

$G -= "Shear stress"/"Shear strain"= (F / A)/ ((Δ x) / l)$
$=>G= (F l)/( A Δ x)" Pa"$

Inserting given values in SI units we get

$G= 10 xx(10/100)/( 0.05/100)$
$=>G= 10 xx(10)/( 0.05)$
$=>G=2.0xx10^3" Pa"$

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Question #2b1f4

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