A 17.2*g17.2g mass of ethylene glycol was dissolved in a 500*g500g mass of water to give a solution of 515*mL515mL volume. What are....?

"(i) Molarity..."(i) Molarity...
"(ii) Molality..."(ii) Molality...
"(iii) Percentage by mass..."(iii) Percentage by mass...
"(iv) Moles fractions of each component..."(iv) Moles fractions of each component...

1 Answer
Feb 2, 2017

"Moles of solute"Moles of solute == (17.2*g)/(62.07*g*mol^-1)=0.277*mol17.2g62.07gmol1=0.277mol

Explanation:

"Molarity"="Moles of solute"/"Volume of solution"=(0.277*mol)/(0.515*L)Molarity=Moles of soluteVolume of solution=0.277mol0.515L

~=0.50*mol*L^-10.50molL1

"Molality"="Moles of solute"/"Kilograms of solvent"=(0.277*mol)/(0.500*kg)Molality=Moles of soluteKilograms of solvent=0.277mol0.500kg

~=0.50*mol*kg^-10.50molkg1

"Percentage by mass"Percentage by mass == "Mass of solute"/"Mass of solution"xx100%Mass of soluteMass of solution×100%

=(17.2*g)/(17.2*g+500*g)xx100%=3.33%(m/m)=17.2g17.2g+500g×100%=3.33%(mm)

"Mole fraction, "chi_"diol"Mole fraction, χdiol == "Moles of diol"/"Moles of diol + moles of solvent"Moles of diolMoles of diol + moles of solvent

=(0.277*mol)/(0.277*mol+(500*g)/(18.01*g*mol^-1))~=0.001=0.277mol0.277mol+500g18.01gmol10.001

What is chi_"water"χwater?