Which of the given solutions should display the GREATEST departure from the freezing point, and the boiling point of the water solvent?

A. LiCl(aq)
B. NaCl(aq)
C. sucrose(aq)
D. Na3PO4(aq)
E. MgBr2(aq)

1 Answer
Jan 30, 2017

Probably D if EQUAL, formal concentrations of each salt were prepared.

Explanation:

The more particles in solution, the greater the freezing point depression, and the greater the boiling point elevation

All these solutes speciate in aqueous solution to give a number of different particles:

A. LiCl(s)Li++Cl

B. NaCl(s)Na++Cl

C. sucrose(s)sucrose(aq)

D. Na3PO4(s)+H2O3Na++HPO4+HO

E. MgBr2(s)Mg2++2Br

Clearly the phosphate ion delivers the most species, the most ions, in aqueous solution. And thus this species should give the greatest boiling point elevation.