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Question #8deff

1 Answer

Jul 17, 2017

The limit is #0#.

Explanation:

#lim_(xrarr3^+)(x-3)/sqrt(x^2-9) = lim_(xrarr3^+)((x-3)sqrt(x^2-9))/(x^2-9)#

# = lim_(xrarr3^+)((x-3)sqrt(x^2-9))/((x-3)(x+3))#

# = lim_(xrarr3^+)sqrt(x^2-9)/(x+3)#

# = 0/6 = 0#

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