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How do we solve the equation $2sinx+sinxcosx=0$ ?

1 Answer

Shwetank Mauria

May 22, 2017

$x={0,pi,2pi}$

Explanation:

$2sinx+sinxcosx=0$ can be written as

$sinx(2+cosx)=0$

As range for $cosx$ is $[-1,1]$ , $2+cosx >0$ and dividing both sides by $2+cosx$ , we get

$sinx=0$ and in the domain $0 <=x <= 2pi$

$x={0,pi,2pi}$

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