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Question #7d2f5

1 Answer

Nov 16, 2017

#1/2x+cosx+c#

Explanation:

#int(1/2-sinx )dx#

#=int1/2dx-intsinxdx# #color(white)(blan)# using#(intf(x)+g(x)dx=intf(x)dx+intg(x)dx)#

#=1/2x-(-cosx)+c##color(white)(blan)# #(intsinxdx=-cosx+c)#

#=1/2x+cosx+c#

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