Question #a03f5

Question

Question #a03f5

1 Answer

Impact of this question

2647 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-14T00:25:57

$26 . ¯ 6 rad \cdot s^{- 2}$ $26.bar6" rad"cdot"s"^-2$

Explanation:

Expression connecting angular velocity $ω$ $omega$ and rpm is

$ω = 2 π f$ $omega=2pif$
where $f$ $f$ is revolution per second.

In the given problem
Initial angular velocity $ω_{i} = 2 π \times \frac{1200}{60} = 20 π rad \cdot s^{- 1}$ $omega_i=2pixx1200/60=20pi" rad"cdot"s"^-1$
Final angular velocity $ω_{f} = 2 π \times \frac{3000}{60} = 100 π rad \cdot s^{- 1}$ $omega_f=2pixx3000/60=100pi" rad"cdot"s"^-1$
Change in angular velocity $Delta omega=(100-20)pi=80pi" rad"cdot"s"^-1$
Average Rotational or Average Angular acceleration $baralpha-=(Deltaomega)/(Deltat)$
Therefore we have Average Angular acceleration $bar alpha=(80pi)/3$
$=26.bar6" rad"cdot"s"^-2$

Science

Math

Humanities

... and beyond

Question #a03f5

1 Answer

Explanation:

Related questions

Impact of this question